Solution : Question 79: A road crosses a railway line at an angle of 30° as shown in the figure. So, their sum is 180°. ∵ AB is a straight line. From (i), Give reason. Now, PQ || RS and PR is a transversal. Which player has the best kicking angle? Vertically opposite angles are always In the given figure, POQ is a line. In the given figure, PQ || SR and SP|| RQ. Question 76. ; Question 99: (d) In figure (d), a and bare adjacent angles since, they have a common vertex, common arm and also, their non-common arms are on either side of common arm. ∠1, ∠3; ∠2, ∠4. (a) vertically opposite angles Putting value of x in (i), we get ∠3 =∠6 ∠4=∠5 . Solution: Solution: In the given figure, PO || RS, TR || QU and ∠PTR = 42°. ⇒ 2x = 166° ∴ EF and GH are not parallel lines. ⇒ ∠y = 180° – 35° = 145° ⇒ ∠ABC = 180° – 120° [Using (ii)] (d) 154° Solution: 5. Because linear pair is always in a straight line and straight line makes 180° angle. ⇒ y = 90° – 60° = 30° Solution : Question 103: \(\Rightarrow x=\frac{120^{\circ}}{2}=60^{\circ}\) Question 70. Solution: (d) Two angles are called adjacent angles, if they have a common vertex and a common arm but no common interior points. Parallel Two lines in a plane which do not meet at a point anywhere, are called________lines. ⇒ 120° + ∠z= 180° [Using (i)] Write down each pair of adjacent angles shown in the following figures. NCERT Exemplar Class 7 Maths Chapter 5 Lines and Angles are part of NCERT Exemplar Class 7 Maths. A line segment has two end points. (a) Since, PQ || SR and RP is a transversal Then, its supplement will be (180° – x). In the given figure, PQ || RS and a : b =3 : 2. Two supplementary angles are always obtuse angles. (i) b and c (ii) Let the angle between d and e is ∠2. Now, PQ || RT and RQ is a transversal. With this article, you will get solutions to all the questions of CBSE Class 7 Maths, Chapter 5 – Lines and Angles. Both angles of a pair of supplementary angles can never be acute angles. Let each angle be x. In (given figures) are the following pairs of angles adjacent? ∴ ∠ABP = ∠CBQ ——– (1) Also, a || d and f is a transversal. (d) supplementary Maths Class 5 Lines and Angles Exercise 5.2 NCERT Solutions are extremely helpful while doing your homework or while preparing for the exam. ∴ 90°- x = 79° ⇒ 4x = 90° – 2 = 88° In the given figure, AB || CD. Solution : NCERT Exemplar Problems Class 7 Maths – Triangles Question 1: The sides of a triangle have lengths (in cm) 10, 6.5 and a, where a is a whole number. (ii) EF is a straight line. (a) 10° So, the sum of angles forming linear pair is 180°. Solution : ⇒ 3a – b + 2a + b = 180 ⇒ 5a = 180 Solution: 90°, Question 55. Question from very important topics are covered by NCERT Exemplar Class 7.You also get idea about the type of questions and method to answer in your Class 7th examination. \(\Rightarrow b=\frac{100^{\circ}}{5}=20^{\circ}\). This chapter throws light on topics such as related angles, pair of lines. Question 77. False ∴ Supplement of x = 180° – 28° = 152°, Question 88. An angle is more than 45°. Solution: ∠1 and ∠8; ∠2 and ∠7; ∠3 and ∠4; ∠4 and ∠5; ∠5 and ∠6; ∠3 and ∠6 are six pairs of supplementary angles. Construct a line l parallel to AB, passing through F. l is parallel to both AB and CD. Then, AOB will be a straight line and sum of all the angles on a straight line is 180°. Question 31: ⇒ ∠BCD = 180°- 50° = 130° As, if we subtract an angle which is less than 90° from 180°, then result will be an angle greater than 90°. Let x be the supplement of the right angle. ⇒ f = 108°, Question 37. Solution: \(\Rightarrow \quad a=\frac{120^{\circ}}{6}=20^{\circ}\) According to question, ⇒ 3x = 180° x + 61° = 180° [Linear pair] Solution: Linear pair angles are supplementary angles as their sum is 180°. In the given figure, PQ || ST. Then, the value of x + y is If the complement of an angle is 799, then the angle will be of Question 104. e.g. Since, AB || l and EF is a transversal. In the given figure, the value of x is Question 86: (b) We know that angle of incident and angle of reflection is same. (a) how many angles are formed? If ∠1 = (2a + b)° and ∠6 = (3a – b)° , then the measure of ∠2 in terms of b is Find ∠PQR. Vertically opposite angles are either both acute angles or both obtuse angles. Given that. Question 35: \(\Rightarrow \angle P O R=\frac{90^{\circ}}{6}=15^{\circ}\) \(\Rightarrow \quad x=\frac{210}{6}=35\) Now, a + b = 45° + 55° = 100°, Question 105. (a) Complementary angles are those whose sum is 90°. Which is given below, students can direct access from the given link. Question 61: (d) 144° Question 100: Two lines AB and CD intersect at 0 (see the figure). ⇒ x = 180° – 61°= 119°. Vertically opposite angles are always Angles between South and West and South and East are ⇒ 50° + ∠BCD = 180° 60° + y = 90° If you have any query regarding NCERT Solutions for Class 7 Maths Chapter 5 Lines and Angles Ex 5.2, drop a comment below and we will get back to you at the earliest. (b) Since, POQ is a straight line Then, x + 90° = 180° ⇒ x = 180° – 90° = 90°. \(\Rightarrow \quad y=\frac{180^{\circ}}{9}=20^{\circ}\), Question 17. Solution : (a) Since, POR is a line. (c) Draw a line l parallel to QP. It is given that other angle is one-third of first. Question 85: Two angles are said to be complementary angles, if their sum is 90°. If you have any query regarding NCERT Solutions for Class 7 Maths Chapter 5 Lines and Angles, drop a comment below and we will get back to you at the earliest. Question 51: (c) four pairs of adjacent angles. Free PDF download of Important Questions with solutions for CBSE Class 7 Maths Chapter 5 - Lines and Angles prepared by expert Mathematics teachers from latest edition of CBSE(NCERT) books. Since, lines l, n are parallel and q is transversal. (a) 5b + 2a = 180° [Linear pair] = (x-x) + (190°-10°)=0 + 180°= 180° Thus, one angle is 45° and other is 180° – 45° = 135°, Question 98. True In the given figure, if QP|| SR, the value of a is The angles x and 90°- x are Doing worksheets are important to check your understanding of various concepts. ⇒ 4x + 4 = 180° ⇒ 4x = 180°- 4 = 176° Its complementary angle must be less than 45°. Then, the complement of x will be (90 – x)°. ∴ x + 2y + 3y = 180° This chapter deals with the basics of Geometry, parallel lines and transversal, pair of lines, angles and its types, Related angles and interior and exterior angles of triangles. (b) 90° (c) If one of the angles is right, then other angle of a linear pair is also right. ∴ ∠QOS = 5 ∠POR = 5 × 15° = 75°, Question 23. CBSE Worksheets for Class 7 Maths: One of the best teaching strategies employed in most classrooms today is Worksheets. False ∴ ∠COD = 90° Solution : (c) PQ || RS, line l is a transversal. ∠a = ∠3 [Vertically opposite angles] b: If a transversal intersects, two other lines, then the sum of two interior angles on the same side of the transversal is 180°. False Thus, m || n as the sum of co-interior angles is 180°. \(\Rightarrow x=\frac{180^{\circ}}{5}=36^{\circ}\) (a) ∠1+ ∠5=180° (b) ∠2 + ∠5=180° \(\Rightarrow x=\frac{180^{\circ}}{3}=60^{\circ}\) False ∠1 +∠2 = 180° [Angles on a straight line PQ] (a) 20° Solution: ⇒ a = 180° – 85° = 95°. We know that the sum of the measures of the supplementary angles is 180°. (b) 50°, 20° Question 33. (a) 20° (i) Name all the pairs of adjacent angles. (c) 122° (b) Two angles are called adjacent angles, if they have a common vertex and a common arm but no common interior points. Find the measures of the angles. The supplement of an obtuse angle is always _________ angle. (d) (ii) is false It is given that, the angle 60° less than 2 times of its supplement. From the given figure, we have Then, the angles are Question 59: From (i) and (ii), we have Solution: Find the measures of the angles. Hence, ∠AOC and ∠BOC are supplementary angles. (c) Since, AB and CD are parallel and PR is a transversal. Question 7: Let two consecutive odd integers x, x + 2. If the sum of measures of two angles is 90%, then the angles are _________ (iii) uncommon arms are always opposite rays. True / False The difference of two complementary angles is 30°. Solution: In the given figure, if PQ || RS and QR || TS, then the value of a is (c) ∠3 + ∠8=180° (d) ∠2 + ∠3=180° ∴ ∠AOD + ∠AOC = 180° [Linear pair] Solution: Check the below NCERT MCQ Questions for Class 7 Maths Chapter 5 Lines and Angles with Answers Pdf free download. Now, l || m and p is a transversal. Thus, x = 110° and y = 100°. Hence, both angles make a linear pair. In the given figure, PO || SR and SP | RQ. (b) Since, PA || BC and AB is a transversal. NCERT Exemplar Class 7 Maths Solutions Chapter 5: Lines and angles In this chapter you will learn about complementary angles, adjacent angles, perpendicular lines and parallel lines. (a) ∠a = b Two lines in a plane which do not meet at a point anywhere are called _________ lines. Since, 90° + 90° = 180°, a supplementary angle. Now, l || m and AC is a transversal. (b) ∠PQT and ∠TOR; ∠SQR and ∠PQS are two pairs of supplementary angles. Therefore, B will be less than 45°. Question 82: ⇒ ∠2 = 180° – (2a+ b)° ——– (ii) [∵ ∠1 = (2a + b)° (given)] ∴ x + y = 90° ———(i) [Angles are complementary] NCERT Solutions for Class 7 Maths Chapter 5 – Lines and Angles Exercise 5.1 : Solutions of Questions on Page Number : 101 Q1 : Find the complement of each of the following angles: (c) 80 According to question, x + x = 166° Now, QP || RS and PR is a transversal. ∴ Sum of these two angles = 90° + 90° = 180° (iv) Let the angle between c and fig ∠4. In the given figure, QP || RS. (b) Supplementary angles are those whose sum is 180°. Solution: (i) EF and GH Solution : Write the correct one. ⇒ 100° + a = 180° (b) Following types of angles are formed: These NCERT Solutions for Class 7 Maths Lines and Angles in Hindi medium pdf download have innumerable benefits as these are created in simple and easy-to-understand language. Acute Solution : ∴ x = 110° [Alternate interior angles] Hence, ∠5 =∠8. Find the reflex ∠EFG. Can two acute angles form a pair of supplementary angles? (d) ∠4 = ∠8 \(\Rightarrow \quad a=\frac{180}{5}=36\) Question 59. (b) If one angle is obtuse angle, then other angle will be acute. Thus, the greater angle is 100°. ∴ a = 3x = 3 × 36° = 108° Two adjacent angles always form a linear pair. In which of the following figures, a and b are forming a pair of adjacent angles? NCERT Solutions for Class 6, 7, 8, 9, 10, 11 and 12. Question 49: In the given figure, POR is a line. Following are vertically opposite angles and linear pair in the above figure: Question 74: Question 112. Mathematics NCERT Grade 7, Chapter 5: Lines and Angles is all about different lines, line segments, and angles. ∴∠PAB = ∠ABC [Alternate interior angles] It is given that, the angle is four times its supplement. ∠POR and ∠ROQ; ∠ROQ and ∠OOS; ∠QOS and ∠SOP; ∠SOP and ∠POR; ∠ROT and ∠TOS; ∠OOT and ∠POT are linear pairs. Name the pairs of supplementary angles in the following figures: (c) Since, angles are on a straight line. Hence, the two angles are supplementary, as their sum is 180°. Following are the pairs of supplementary angles in the above figures: Question 75: In the given figure, AE || GF || BD, AB||CG|| DF and ∠CHE = 120°. Thus, ∠COF = 110°, Question 95. True Solution : False ∴ Its supplement = 180° – x False Two angles are called adjacent angles, if they have a common vertex and a common arm but no common interior points. ∴ x + y = 180° ———– (i) Solution : Question 21. p : a and b are forming a linear pair. The type of questions that will be asked from NCERT Class 9 Maths Unit 6 are displayed in the below provided NCERT Exemplar Class 9 Maths Unit 6. Students can access the NCERT MCQ Questions for Class 7 Maths Chapter 5 Lines and Angles Pdf free download aids in your exam preparation and you can get a good hold of the chapter. l || m and QR is a transversal. NCERT Exemplar for Class 7 Maths Chapter 5 with Solutions by Swiflearn are by far the best and most reliable NCERT Exemplar Solutions that you can find on the internet. ⇒ ∠2 = ∠y = 120° [Vertically opposite angles] Thus, ∠x = 60°, ∠y = 120°and ∠z = 60°, Question 92. Vertically opposite angles form a linear pair. ⇒ b = 180° – 132° = 48° We have, With the help of it, candidates can prepare well for the examination. (c) 55° \(\Rightarrow \quad x=\frac{180^{\circ}}{4}=45^{\circ}\) (d) 101° Complementary (a) 44° (c) ∠1 and ∠3; ∠2 and ∠4 are the two pairs of vertically opposite angles. Two angles making a linear pair are always supplementary. Check NCERT Solutions for Class 7 Mathematics. Solution: In the given figure, PQ || RT. ∴ 4c = 3b [Corresponding angles] (d) Vertically opposite angles are always equal. 90° – x = 62° Question 82. This chapter deals with the basics of Geometry, parallel lines and transversal, pair of lines, angles and its types, Related angles and interior and exterior angles of triangles. Question 66. Our experts have designed exemplar problems in accordance with CBSE syllabus (2020-2021) for 9th standard, which covers the following topics of chapter Lines and Angles given below;. l || m and PQ is a transversal Let one angle be x. ∴ ∠POR + ∠ROT + ∠TOQ = 180° Question 68. In the given figure, find out which pair of lines are parallel: In the given figure, line l intersects two parallel lines PQ and RS. (d) equal In the given figure, OR ⊥ OP. Amisha makes a star with the help of line segments a, b, d, e and f, in which a || d, b || e and c || f. Chhaya marks an angle as 120° as shown in figure, and asks Amisha to find the ∠x, ∠y and ∠z. Solution: As, if we subtract an acute angle from 180°, we get an angle which is greater than 90°. (a) If one of the angles is acute, then other angle of a linear pair is obtuse. (d) 22.5° Solution : True (c) 90° Solution : Thus, the required angles are 60° and 30°. Solution : ⇒ ∠2 = 180° – 75° = 105° Then, ∠QOS measures (a) Since, PQ || RS and RQ is a transversal ⇒ 5x = 180° It is the most important topic in the Maths for class 7 as well as upper. The angles x – 10° and 190° – x are Solution : Which of the following is false? In the given figure, are the following pairs of angles adjacent? Find the complement of each of the following angles: Solution: Complement of the angle 20° = 90° – 20° = 70° Complement of the angle 63° = 90° – 63° = 27° Complement of the angle 57° = … Solution : (a) 110° Find the values of a and b. Solution : Question 110: angle between South and East is 90°. (c) 136° No. Therefore, angles given in option (b) are supplementary as well as vertically opposite. (a) 95°, 85° Question 47: ⇒ 720° = 5x Interior angles on the same side of a transversal with two distinct parallel lines are supplementary angles. (b) PQ is a straight line. NCERT Exemplar Class 7 Maths Chapter 5 Lines and Angles are part of NCERT Exemplar Class 7 Maths. NCERT Exemplar Class 9 Mathematics Chapter 6 Lines and Angles, is provided in pdf format for students to prepare for exams. We hope the NCERT Exemplar Class 7 Maths Chapter 5 Lines and Angles will help you. (c) 36° Find the angles. Students can access the NCERT MCQ Questions for Class 7 Maths Chapter 5 Lines and Angles Pdf free download aids in your exam preparation and you can get a good hold of the chapter. (a) 60°, 30° (b) 70°, 40° All the solutions of Lines And Angles - Mathematics explained in detail by experts to help students prepare for their CBSE exams. ⇒ 5b – 180° – 80° = 100° Thus, the required angle is 119°. Thus the required angles are 90° each. True (a) It is given that the angles are in the ratio of 1 : 2. (a) ∠1 = ∠5 (b) ∠4 = ∠8 (c) ∠5 = ∠8 (d) ∠3 = ∠7 In the given figure, a=40°. Solution : (c) Since, PQ || RS and line 1 is a transversal. Question 23: It is given that both are supplementary angles. Solution: Question 75. ⇒ (3a + 5)° + (2a-25)° = 180° a and b are on the opposite side of transversal l. (b) 144° Check NCERT Solutions for Class 7 Mathematics. ∴∠CHE = ∠HCB – 120° ———- (i) [Alternate interior angles] Solution : Question 101: (a) ∠TOS and ∠SQR is a pair of complementary angles. Which player has the best kicking angle? ⇒ ∠CDE-120° ——- (ii) [Using (1)] Two angles making a linear pair are always adjacent angles. Solution: Two angles are making a linear pair. (a) one of its angle is acute? (ii) each linear pair. Solution : Question 112: e.g. As, PQ is a straight line. If angle P and angle Q are supplementary and the measure of angle P is 60°, then the measure of angle Q is The measure of an angle which is four times its supplement is (c) 72° (d) 105°, 75° In the given figure, line l intersects two parallel lines PQ and RS. Since, POQ is a line. If we add 60° and 70°, we get 60°+ 70° = 130° <180° ∴ ∠1 = ∠2 [Alternate interior angles] Solution: i.e. (a) Let one of the angle be x. (a) interior angles on the same side of the transversal ⇒ ∠z = 180° – 120° = 60° (d) both are obtuse (c) adjacent (d) equal (d) Let the angle be x. NCERT Solutions for Class 7 Maths Chapter 5 Lines and Angles can be of great value if you are trying to excel in your school examinations. Solution : Solution : Now, p || q and n is a transversal. We hope the NCERT Solutions for Class 7 Maths Chapter 5 Lines and Angles Ex 5.2 help you. Question 105: NCERT Solutions for Class 7 Maths Chapter 6 … and x – y = 30° ——— (ii) [Given] Measures (in degrees) of two supplementary angles are consecutive odd integers. (d) From the given Figure it is clear that, ∠a = ∠b and ∠c= ∠d, Question 12: In the given figure, 4m and a line t intersects these lines at P and Q, respectively. Find the values of a, b and c. ⇒ x° = 90° – 79°= 11° You can find NCERT Solutions for Class 7 Maths Chapter 5 Lines and Angles Exercise 5.1 here that will be helpful in knowing the important points and formulas given in the exercise. Question 87. ⇒ 60° + ∠2 = 180° [Using (ii)] Two angles making a linear pair are always adjacent angles. NCERT Exemplar for Class 7 Maths Chapter 5 Lines and Angles With Solution . Degrees ) of two right angles are called _________ lines get an is!: When two lines at p and q, respectively get the result than. 55° [ Alternate interior angles are always equal but do not meet at a point anywhere, are the of. 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